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Recall the classification of quadrilaterals. Begin by finding the slopes of the sides of the quadrilateral.
Type of Parallelogram: Parallelogram, none of the mentioned.
Explanation: See solution.
Let's plot the given points on a coordinate plane and graph the quadrilateral.
Quadrilateral | Definition |
---|---|
Rhombus | Parallelogram with four congruent sides |
Rectangle | Parallelogram with four right angles |
Square | Parallelogram with four congruent sides and four right angles |
Now, let's find the slopes of the sides using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | Simplify |
---|---|---|---|
JM | ( - 2,- 1), ( 3,1) | 1-( - 1)/3-( - 2) | 2/5 |
ML | ( 3,1), ( 1,5) | 5- 1/1- 3 | - 2 |
LK | ( 1,5), ( - 4, 3) | 3- 5/- 4- 1 | 2/5 |
KJ | ( - 4, 3), ( - 2,-1) | - 1- 3/- 2-( - 4) | - 2 |
We can tell that consecutive sides are not perpendicular, as their slopes are not opposite reciprocals. - 2(2/5 ) ≠-1 Therefore, our quadrilateral is either a parallelogram or a rhombus. To check this, we can find the lengths of its sides using the Distance Formula.
Side | Points | d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2) | Simplify |
---|---|---|---|
JM | ( - 2,- 1), ( 3,1) | sqrt(( 3-( - 2))^2+( 1-( -1))^2) | sqrt(29) |
ML | ( 3,1), ( 1,5) | sqrt(( 1- 3)^2+( 5- 1)^2) | 2sqrt(5) |
LK | ( 1,5), ( - 4, 3) | sqrt(( - 4- 1)^2+( 3- 5)^2) | sqrt(29) |
KJ | ( - 4, 3), ( - 2,-1) | sqrt(( - 2-( - 4))^2+( - 1- 3)^2) | 2sqrt(5) |
Our parallelogram has two pairs of congruent sides. Therefore, the most precise name for this quadrilateral is a parallelogram.