5. Rhombi and Squares
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Recall the classification of quadrilaterals. Begin by finding the slopes of the sides.
Type of Parallelogram: Rhombus.
Explanation: See solution.
Let's plot the given points on a coordinate plane and graph the parallelogram.
Quadrilateral | Definition |
---|---|
Rhombus | Parallelogram with four congruent sides |
Rectangle | Parallelogram with four right angles |
Square | Parallelogram with four congruent sides and four right angles |
Now, let's find the slopes of the sides using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | Simplify |
---|---|---|---|
JM | ( - 4,- 1), ( - 1,3) | 3-( - 1)/- 1-( - 4) | 4/3 |
ML | ( - 1,3), ( 4,3) | 3- 3/4-( - 1) | 0 |
LK | ( 4,3), ( 1, -1) | -1- 3/1- 4 | 4/3 |
KJ | ( 1, -1), ( - 4,-1) | -1-( -1)/- 4- 1 | 0 |
We can tell that consecutive sides are not perpendicular, as their slopes are not opposite reciprocals. 0 (4/3 ) ≠-1 Therefore, our quadrilateral is either a parallelogram or a rhombus. To check this, we can find the lengths of its sides using the Distance Formula.
Side | Points | d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2) | Simplify |
---|---|---|---|
JM | ( - 4,- 1), ( - 1,3) | sqrt(( - 1-( - 4))^2+( 3-( -1))^2) | 5 |
ML | ( - 1,3), ( 4,3) | sqrt(( 4-( - 1))^2+( 3- 3)^2) | 5 |
LK | ( 4,3), ( 1, -1) | sqrt(( 1- 4)^2+( -1- 3)^2) | 5 |
KJ | ( 1, -1), ( - 4,-1) | sqrt(( - 4- 1)^2+( - 1-( -1))^2) | 5 |
Our parallelogram has four congruent sides. Therefore, the most precise name for this quadrilateral is a rhombus.