Let's look at the given picture. Since we know that all crosswalks are the same length, we will recall that a quadrilateral with all sides congruent can be either a rhombus or a square.
In our exercise, we are given that the angle between two streets has a measure of 29^(∘). This means that one of the angles of this quadrilateral is also 29^(∘), as it creates a pair of vertical angles with the given one.
Notice that a square has four right angles, as it is both a rectangle and a rhombus. Therefore, this quadrilateral cannot be a square because it has an angle that is not a right angle. This means that this quadrilateral is a rhombus.
