McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
5. Rhombi and Squares
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Exercise 23 Page 518

The diagonals of a rhombus are perpendicular.

9

Practice makes perfect

We want to find the length AP. Let's analyze the given rhombus.

We are given the lengths AB=15 and PB=12. Note that the diagonals in a rhombus are perpendicular. Therefore, △ ABP is a right triangle with legs AP and PB, and hypotenuse AB. We can use the Pythagorean Theorem to calculate AP. AP^2+PB^2=AB^2 ⇕ AP^2+12^2=15^2 Let's solve the above equation for AP.
AP^2+12^2=15^2
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Solve for AP
AP^2+144=225
AP^2=81
AP=9
Note that, when solving the above equation, we kept the principal root. This is because AP is a side length and therefore must be positive. We found that AP= 9.