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Recall the classification of quadrilaterals. Begin by finding the slopes of the sides.
Type of Parallelogram: Parallelogram, none of the mentioned.
Explanation: See solution.
Let's plot the given points on a coordinate plane and graph the parallelogram.
Quadrilateral | Definition |
---|---|
Rhombus | Parallelogram with four congruent sides |
Rectangle | Parallelogram with four right angles |
Square | Parallelogram with four congruent sides and four right angles |
Now, let's find the slopes of the sides using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | Simplify |
---|---|---|---|
QR | ( - 2,-1), ( - 1,2) | 2-( -1)/- 1-( - 2) | 3 |
RS | ( - 1,2), ( 4,1) | 1- 2/4-( - 1) | - 1/5 |
ST | ( 4,1), ( 3, -2) | -2- 1/3- 4 | 3 |
TQ | ( 3,- 2), ( - 2,- 1) | -1-( -2)/- 2- 3 | - 1/5 |
We can tell that consecutive sides are not perpendicular, as their slopes are not opposite reciprocals. 3 ( - 1/5 ) ≠-1 Therefore, our quadrilateral is either a parallelogram or a rhombus. To check, we can find the lengths of its sides using the Distance Formula.
Side | Points | d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2) | Simplify |
---|---|---|---|
QR | ( - 2,- 1), ( - 1,2) | sqrt(( - 1-( - 2))^2+( 2-( -1))^2) | sqrt(10) |
RS | ( - 1,2), ( 4, 1) | sqrt(( 4-( - 1))^2+( 1- 2)^2) | sqrt(26) |
ST | ( 4, 1), ( 3, -2) | sqrt(( 3- 4)^2+( -2- 1)^2) | sqrt(10) |
TQ | ( 3, -2), ( - 2,-1) | sqrt(( - 2- 3)^2+( -1-( -2))^2) | sqrt(26) |
Our quadrilateral has two pairs of sides of different lengths. Therefore, the most precise name for this quadrilateral is a parallelogram, then it's none of the mentioned.