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Recall the classification of quadrilaterals. Begin by finding the slopes of the sides.
Type of Parallelogram: Rectangle, rhombus, square.
Explanation: See solution.
Let's plot the given points on a coordinate plane and graph the parallelogram.
Quadrilateral | Definition |
---|---|
Rhombus | Parallelogram with four congruent sides |
Rectangle | Parallelogram with four right angles |
Square | Parallelogram with four congruent sides and four right angles |
Now, let's find the slopes of the sides using the Slope Formula.
Side | Points | y_2-y_1/x_2-x_1 | Simplify |
---|---|---|---|
QR | ( 1,2), ( - 2,- 1) | - 1- 2/- 2- 1 | 1 |
RS | ( - 2, - 1), ( 1, -4) | -4-( - 1)/1-( - 2) | - 1 |
ST | ( 1, -4), ( 4, -1) | -1-( -4)/4- 1 | 1 |
TQ | ( 4, -1), ( 1,2) | 2-( - 1)/1- 4 | - 1 |
Note that the slopes of consecutive sides are opposite reciprocals. 1 ( - 1 ) = -1 Therefore, the consecutive sides are perpendicular. This means that the four angles of the quadrilateral are right angles. As a result, our parallelogram is a rectangle. Let's now calculate the lengths of the sides using the Distance Formula.
Side | Points | d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2) | Simplify |
---|---|---|---|
QR | ( 1,2), ( -2,-1) | sqrt(( - 2- 1)^2+( - 1- 2)^2) | 3sqrt(2) |
RS | ( - 2,- 1), ( 1, -4) | sqrt(( 1-( - 2))^2+( -4-( - 1))^2) | 3sqrt(2) |
ST | ( 1, - 4), ( 4, -1) | sqrt(( 4- 1)^2+( -1-( -4))^2) | 3sqrt(2) |
TQ | ( 4, -1), ( 1,2) | sqrt(( 1- 4)^2+( 2-( -1))^2) | 3sqrt(2) |
Since all the sides have the same length, our parallelogram has four congruent sides. Therefore, it is a rhombus. A rectangle that is also a rhombus is a square.