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Can both events occur at the same time?
Mutually exclusive or not? Not mutually exclusive.
Probability: 413 or about 30.8 %
We want to determine whether the events are mutually exclusive and find the probability of their union. We will do these things one at a time.
Events that cannot occur at the same time are mutually exclusive. Mutually exclusive events have no outcomes in common. For example, because it is not possible to toss a coin and obtain heads and tails at the same time, these two events are mutually exclusive.
| Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A and B will occur is P(AandB)=0. | If A and B are not mutually exclusive events, the probability that A and B will occur is P(AandB)≠0. |
Let A be drawing an ace
and B be drawing a heart
from a standard deck of cards.
One out of the four aces is a heart, so it is possible to be both an ace and a heart in the given deck. Therefore, A and B are not mutually exclusive events.
Now, we can find the probability that the card drawn is either an ace or a heart.
| Addition Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B). | If A and B are not mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B)-P(AandB). |
We know that there are 52 cards in the deck. Out of these, 4 cards are aces, 13 cards have a heart suit, and only 1 card is the ace of hearts. Next, we can calculate P(A), P(B), and P(AandB). P(A)&=4/52 l← ← lAces Total cards [0.5em] P(B)&=13/52 l← ← lHearts Total cards [0.5em] P(AandB)&=1/52 l← ← lAce of hearts Total cards Finally, considering that A and B are not mutually exclusive events, let's calculate P(AorB).
Substitute values
Calculate quotient
Round to 3 decimal place(s)
Convert to percent
We found that P(ace or heart) is equal to 413 or about 30.8 %.