McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
6. Probabilities of Mutually Exclusive Events
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Exercise 38 Page 931

Notice that in order to find the number of peppermints in the bag, we need to multiply the total number of candies in the bag by the probability of choosing a peppermint.

B

Practice makes perfect

We know the bag contains 60 pieces of candy. There are only 3 types of candy in the bag: peppermint, chocolate, and butterscotch. Let's denote their numbers as p, c, and b, respectively.

  • p — number of peppermints in the bag
  • c — number of chocolates in the bag
  • b — number of butterscotch candies in the bag
We know that a probability of choosing a peppermint is 0.25. This allows us to find the number of peppermints in the bag p. We need to multiply the total number of candies in the bag by the probability of choosing a peppermint.

p = 60 * 0.25 = 15 We are also given the probability of choosing a chocolate 0.3, therefore we can find the number of chocolates in the bag, too. c = 60 * 0.3 = 18 There are only 3 types of candy in the bag, so we can obtain the number of butterscotch candies by subtracting the number of peppermints and chocolates from the total number of candies in the bag. p = 60 - 15 - 18 = 27 There are 27 butterscotch candies in the bag. This corresponds to answer B.