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If A and B are events that have outcomes in common, then P(AorB) = P(A)+P(B)-P(AandB).
14/25 or 56 %
Events are mutually exclusive when they cannot occur at the same time. Or, they are considered overlapping when they have outcomes in common. The following rules apply for the probability of these types of compound events.
| Mutually Exclusive Events | Overlapping Events |
|---|---|
| P(AorB)= P(A)+P(B) | P(AorB)= P(A)+P(B)-P(AandB) |
Let A be player is 14
and B be player plays basketball.
Since some students are both 14 and play basketball, these events are not mutually exclusive. Now, we can find the number of players aged 14 and the number of basketball players aged 14 in the given table.
| Graceland Sports Complex | ||||
|---|---|---|---|---|
| Age | Soccer | Baseball | Basketball | Total |
| 14 | 28 | 36 | 42 | 28+36+ 42= 106 |
| 15 | 30 | 26 | 33 | 30+26+33=89 |
| 16 | 35 | 41 | 29 | 35+41+29=105 |
There are 106 players aged 14. Out of these players, 42 play basketball. Next, we can calculate the number of basketball players and the number of all players in the table.
| Graceland Sports Complex | ||||
|---|---|---|---|---|
| Age | Soccer | Baseball | Basketball | Total |
| 14 | 28 | 36 | 42 | 106 |
| 15 | 30 | 26 | 33 | 89 |
| 16 | 35 | 41 | 29 | 105 |
| Total | 28+30+35=93 | 36+26+41=103 | 42+33+29= 104 | 106+89+105= 300 |
Now, we know that there are 106 players aged 14, 104 basketball players, 42 basketball players aged 14, and 300 players in total. Finally, we can calculate P(A), P(B), and P(AandB). P(A)&=106/300 l← ← lAged14 Total players P(B)&=104/300 l← ← lBasketball Total players P(AandB)&=42/300 l ← ← lBasketball and aged14 Total players With this information we want to find the value of P(AorB).
Substitute values
The probability that a player is 14 or plays basketball is equal to 1425, which can be also written as 56 %.