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P(country or R& B)=? First, we can find the numbers of students that are in range of the circles that represent either country music or R&B.
As we can see, the numbers of students in range of the country or R&B are all numbers but 76. Let's add them up. 63+8+7+10+12+89=189 We found that 189 out of 265 students want country or R&B to be played at the dance. Finally, we can calculate the probability P(country or R& B). P(country or R& B)=189/265≈ 0.713 The probability that a randomly chosen student wants country or R&B to be played at the school dance is equal to about 0.713, or 71.3 %.
P(rock and country or R& B and rock) =? To calculate this probability, we will use the given Venn diagram.
First, we can highlight the students that want country and rock music to be played. These students will be in the intersection of rock and country circles.
Next, let's highlight the students that want R&B and rock music to be played.
Now, we can highlight all the students that want rock and country music or R&B and rock music to be played at the school dance.
Let's add all the colored numbers. 8+10+12=30 We found that 30 out of 265 students want rock and country music or R&B and rock music to be played on the school dance. Finally, we can calculate the probability P(rock and country or R&B and rock). P(rock and country or R& B and rock)= 30/265≈ 0.113 The probability is equal to about 0.113, or 11.3 %.
Let's highlight only the students that want R&B to be played at the dance.
Now, let's remove the students that also want rock music to be played at the dance.
We can see that 7+89= 96 students want R&B but not rock music to be played at the school dance. In total, 265 students took part in the survey. With this information, we are ready to calculate the probability P(R&B but not rock). P(R&B but not rock) =96/265≈ 0.362 The probability is equal to about 0.362, or 36.2 %.
The students that want all three types of music are in the intersection of all the three circles — country, rock, and R&B music.
We found that only 10 out of 265 students are in the intersection of all three circles, and therefore want all three types of music to be played. We can now calculate the probability P(all three). P(all three) =10/265≈ 0.038 The probability is equal to about 0.038, or 3.8 %.