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Can both events occur at the same time?
Mutually exclusive or not? Mutually exclusive.
Probability: 213 or about 15.4 %
We want to determine whether the events are mutually exclusive and find the probability of their union. We will do these things one at a time.
Events that cannot occur at the same time are mutually exclusive. Mutually exclusive events have no outcomes in common. For example, because it is not possible to toss a coin and obtain heads and tails at the same time, these two events are mutually exclusive.
| Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A and B will occur is P(AandB)=0. | If A and B are not mutually exclusive events, the probability that A and B will occur is P(AandB)≠0. |
Let A be drawing a jack
and B be drawing a six
from a standard deck of cards.
There is no card in the deck that is both a jack and a six. Therefore, A and B are mutually exclusive events.
Now we can find the probability that the card drawn is either a jack or a six.
| Addition Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B). | If A and B are not mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B)-P(AandB). |
We know that there are 52 cards in the deck. Out of these, 4 cards are jacks and 4 cards are numbered 6. Now, we can calculate P(A) and P(B). P(A)&=4/52 l← ← lJacks Total cards P(B)&=4/52 l← ← lCards number6 Total cards Finally, considering that A and B are mutually exclusive events, let's calculate P(AorB).
P(A)= 4/52, P(B)= 4/52
Calculate quotient
Round to 3 decimal place(s)
Convert to percent
We found that P(Jack or6) is equal to 213 or about 15.4 %.