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Can both events occur at the same time?
Mutually exclusive or not? Not mutually exclusive.
Probability: 1320 or 65 %
We want to determine whether the events are mutually exclusive and find the probability of their union. We will do these things one at a time.
Events that cannot occur at the same time are mutually exclusive. Mutually exclusive events have no outcomes in common. For example, because it is not possible to toss a coin and obtain heads and tails at the same time, these two events are mutually exclusive.
| Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A and B will occur is P(AandB)=0. | If A and B are not mutually exclusive events, the probability that A and B will occur is P(AandB)≠0. |
We select a number at random from integers 1 to 20. Let A be selecting an even number
and B be selecting a number divisible by 3.
Three out of the ten even numbers are divisible by 3, so it is possible to be both an even number and a number divisible by 3. Therefore, A and B are not mutually exclusive events.
Now, we can find the probability that we select an even number or a number divisible by 3.
| Addition Rules for Probability | |
|---|---|
| If A and B are mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B). | If A and B are not mutually exclusive events, the probability that A or B will occur is P(AorB)=P(A)+P(B)-P(AandB). |
When we select a number from integers 1 to 20, there are 20 numbers to choose from. Out of these, there are 10 even numbers, 6 numbers divisible by three, and 3 even numbers divisible by three. Now, we can calculate P(A), P(B), and P(AandB). P(A)&=10/20 l← ← l Even Total numbers [0.5em] P(B)&=6/20 l← ← l Divisible by3 Total numbers [0.5em] P(AandB)&=3/20 l← ← l Even number divisible by3 Total numbers Finally, considering that A and B are not mutually exclusive events, let's calculate P(AorB).
Substitute values
Add and subtract fractions
We found that P(Even or divisible by3) is equal to 1320, which can be also written as 65 %.