McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. Probabilities of Mutually Exclusive Events
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Exercise 40 Page 931

Neither event affects the probability of the other, making them independent events.

Dependent or independent? Independent.
Probability: 136 or 2.8 %

Practice makes perfect

The two events described in this exercise are rolling a 2 on the first die and rolling a 3 on the second die. Since neither of these events affects the probability of the other, these are independent events. If two events are independent, then the probability of both occurring is the product of their individual probabilities. P(AandB)=P(A)* P(B) Let's start by calculating the probability of rolling a 2 on a die.

A die has 6 sides and 1 of them is numbered two. P(A)&=1/6 l←Sides numbered two ←Total sides P(B) is the probability of rolling a 3 on another die.

The second die also has 6 sides and 1 of them is numbered three. P(B)&=1/6 l←Sides numbered three ←Total sides Finally, according to the formula, to calculate P(AandB) we have to multiply P(A) and P(B).
P(AandB)=P(A)* P(B)
P(AandB)= 1/6* 1/6
P(AandB)=1/36
Convert to percent
P(AandB)=0.027
P(AandB)≈0.028
P(AandB)≈2.8 %
Probability of the given event is equal to 136 or about 2.8 %.