McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
1. Geometric Mean
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Exercise 44 Page 626

Notice that x+y=c.

See solution.

Practice makes perfect

Let's consider a right triangle and draw the altitude to the hypotenuse. We will label all the segments formed.

By applying the Geometric Mean (Leg) Theorem, we can write the following two equations.

c/b = b/x and c/a = a/y From the first equation we have that b^2 = c x, and from the second equation we get a^2 = c y. Next, let's add these two equations. b^2 &= c x + a^2 &= c y a^2 + b^2 &= c( x + y) From the diagram and by the Segment Addition Postulate, we have that x + y = c. Let's substitute this into the latter equation. a^2 + b^2 = c c ⇓ c^2 = a^2 + b^2 The final expression is what the Pythagorean Theorem states.