McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
1. Geometric Mean
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Exercise 61 Page 627

Notice that △ SQR and △ PMN have right angles.

Graph:

Verification: See solution.

Practice makes perfect

Let's use the given coordinates to draw the original figure and its dilated image.

We can see that △ SQR and △ PMN have right angles, ∠ Q and ∠ M, and therefore we know that ∠ Q ≅ ∠ M. Let's use the coordinates of the vertices to find the lengths of the sides of each triangle that include the right angles.
Side Vertices Distance Formula Simplified
First Pair of Sides QS ( 2,-8), ( 2,- 2) sqrt(( 2- 2)^2+( - 2-( - 8))^2) 6
MP ( 7,- 4), (7,- 1) sqrt((7- 7)^2+(- 1-( - 4))^2) 3
Second Pair of Sides QR ( 2,- 8), ( 6,- 8) sqrt(( 6- 2)^2+( - 8-( - 8))^2) 4
MN ( 7,- 4), ( 5,-4) sqrt(( 5- 7)^2+( -4-( - 4))^2) 2

Now, we can find the ratios between the corresponding sides. QS/MP=6/3 = 2 [1.2em] QR/MN=4/2 = 2 We can tell that these ratios are equivalent. Therefore, the lengths of two sides of △ SQR are proportional to the lengths of two corresponding sides of △ PMN, and the included angles are congruent. By the Side-Angle-Side Similarity Theorem, we can conclude that △ SQR is similar to △ PMN. △ SQR ~ △ PMN Therefore, the dilation is a similarity transformation.