We want to find the of the terms in the given expression. To do so we will consider the and separately.
14 x^2y- 21 xy+ 35 xy^2
Let's start by finding the GCF of 14, 21, and 35.
Factors of14:& 1,2, 7,and14
Factors of21:& 1,3, 7,and21
Factors of35:& 1,5, 7,and35
We found that the GCF of the coefficients is 7. To find the GCF of the variables, we need to identify the variables repeated in both terms and write them with their minimum .
\begin{aligned}
\textbf{Factors of }\bm{1^\text{st}}\textbf{ Variable:}&\ x, x^2, y, {\color{#FF0000}{xy}}, x^2y\\
\textbf{Factors of }\bm{2^\text{nd}}\textbf{ Variable:}&\ x, y, {\color{#FF0000}{xy}}\\
\textbf{Factors of }\bm{3^\text{rd}}\textbf{ Variable:}&\ x, y, y^2, {\color{#FF0000}{xy}}, xy^2
\end{aligned}
We see that there is one repeated variable factor, xy.
Thus, the GCF of the expression is 7* xy= 7xy. Now we can write the given expression in terms of the GCF.
14x^2y-21xy+35xy^2 ⇕ 7xy* 2x- 7xy* 3+ 7xy*5y
Finally, we will factor out the GCF.
7xy* 2x- 7xy* 3+ 7xy*5y ⇕ 7xy(2x-3+5y)
To check our answer, we can apply the and compare the result with the given expression.
7xy(2x-3+5y)
14x^2y-21xy+35xy^2
After applying the Distributive Property, the result is the same as the given expression. Therefore, we can be sure our solution is correct!