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McGraw Hill Integrated II, 2012 View details

Study Guide and Review

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Exercise 80 Page 84

To solve this equation take the square root of each side.

16, - 6

Practice makes perfect

To solve a quadratic equation in the form x^2=n, we will take the square root of each side. For any number n≥ 0, if x^2=n then x=±sqrt(n). Keeping this in mind, let's consider the given equation.

(x-5)^2=121

SqrtEqn

sqrt(LHS)=sqrt(RHS)

x-5=±sqrt(121)

CalcRoot

Calculate root

x-5=±11

AddEqn

LHS+5=RHS+5

x=±11+5

We can simplify this result into two separate roots.

x=± 11 + 5
x_1=11+5	x_2=- 11 + 5
x_1=16	x_2=-6

We found that the solutions to the given equation are 16 and - 6. To check our answer we will graph the related function y=(x-5)^2-121 using a calculator.