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McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
Study Guide and Review
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Exercise 45 Page 82

When given the area, divide by the width to find the length.

l = x^2-2x+5 units

Practice makes perfect

The area of a rectangle is its length times the width. In this case, we are given the area as x^3-2x^2+5x and the width as x. Let's substitute those into our formula for area and solve for the length.

A = l * w
SubstituteII

A= x^3-2x^2+5x, w= x

x^3-2x^2+5x = l * x
DivEqn

.LHS /x.=.RHS /x.

x^3-2x^2+5x/x = l
SimpQuot

Simplify quotient

x^2 - 2x + 5 = l
RearrangeEqn

Rearrange equation

l = x^2 - 2x + 5

Therefore, the rectangle's expression for length is x^2-2x+5 units.

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