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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Study Guide and Review

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Exercise 45 Page 82

When given the area, divide by the width to find the length.

l = x^2-2x+5 units

Practice makes perfect

The area of a rectangle is its length times the width. In this case, we are given the area as x^3-2x^2+5x and the width as x. Let's substitute those into our formula for area and solve for the length.

A = l * w

A= x^3-2x^2+5x, w= x

x^3-2x^2+5x = l * x

.LHS /x.=.RHS /x.

x^3-2x^2+5x/x = l

Simplify quotient

x^2 - 2x + 5 = l

Rearrange equation

l = x^2 - 2x + 5

Therefore, the rectangle's expression for length is x^2-2x+5 units.

Subchapter links

1 Adding and Subtracting Polynomials p.81

2 Multiplying a Polynomial by a Monomial p.81

3 Multiplying Polynomials p.81

4 Special Products p.82

5 Using the Distributive Property p.82

6 Solving x^2+bx+c=0 p.83

7 Solving ax^2+bx+c=0 p.83

8 Differences of Squares p.84

9 Perfect Squares p.84

10 Roots and Zeros p.85