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Use the area formula with A=154 and l=w+3. Do not forget to set it equal to zero!
14 in.
We know that the painting is 3 inches longer than it is wide. This means that if we denote the width as w, we can write the length as l = w+3. We also know that the area of the painting is 154 square inches. Let's substitute our information into the equation for the area of a rectangle and solve for w.
A= 154, l= w+3
Distribute w
LHS-154=RHS-154
In order to solve, we need to factor the expression and use the Zero Product Property. Let's look for factors of -154 that have a sum of 3. Since -154 is negative, we need one positive and one negative factor. Furthermore, since 3 is positive, the factor with the larger absolute value is positive.
| Factors | Sum |
|---|---|
| -1, 154 | 153 |
| -2, 77 | 75 |
| -7, 22 | 15 |
| -11, 14 | 3 |
Since our leading coefficient is 1, we can use -11 and 14 as our factors. w^2 + 3w - 154 = (w-11)(w+14) Now we can use the Zero Product Property to solve for w.
Use the Zero Product Property
(I): LHS+11=RHS+11
(II): LHS-14=RHS-14
In this case, w represents a unit of length, so the negative answer can be ignored. We can say the width of the painting is 11 inches. To find the length we need to add 3 to the width, so the length of the painting is 11+3 = 14 inches.