McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Study Guide and Review
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Exercise 51 Page 83

Make sure you rewrite the equation leaving all the terms on one side and that you factor out the greatest common factor if it exists.

4, 2

Practice makes perfect
We want to solve the given equation by factoring.

Factoring

Let's start factoring the expression!
x^2-6x+8=0
x^2-2x-4x+8=0
â–Ľ
Factor out x & - 4
x(x-2)-4x+8=0
x(x-2)-4(x-2)=0
(x-4)(x-2)=0

Solving

To solve this equation, we will apply the Zero Product Property.
(x-4)(x-2)=0
lcx-4=0 & (I) x-2=0 & (II)
lx=4 x-2=0
lx_1=4 x_2=2

Checking Our Answer

Checking our answer
We can substitute our solutions back into the given equation and simplify to check if our answers are correct. We will start with x=4.
x^2-6x+8=0
4^2-6( 4)+8? =0
â–Ľ
Simplify
16-6(4)+8? =0
16-24+8? =0
0=0 âś“
Substituting and simplifying created a true statement, so we know that x=4 is a solution of the equation. Let's move on to x=2.
x^2-6x+8=0
2^2-6( 2)+8? =0
â–Ľ
Simplify
4-6(2)+8? =0
4-12+8? =0
0=0 âś“
Again, we created a true statement. x=2 is indeed a solution of the equation.