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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Study Guide and Review

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Exercise 84 Page 84

Find the length of the side of the large square. Then, use that length to solve for the width of the sidewalk.

12 ft

Practice makes perfect

If we are given the area of a square region, we can find the length of its side. Once we find the length of the side, we can subtract to find what is left for the length of the sidewalk. The area of the whole region is 900 ft^2. Let's find the length of the side of a square with area 900.

A = s^2

A= 900

900=s^2

sqrt(LHS)=sqrt(RHS)

± 30 = s

Rearrange equation

s = ± 30

Since s is a length, we can ignore the negative value. Let's call the width of the sidewalk x and put the dimensions of the region in the picture.

From the picture we can write an equation and solve for x.

x + x + 6 = 30

Add terms

2x + 6 = 30

LHS-6=RHS-6

2x = 24

.LHS /2.=.RHS /2.

x=12

The width of the sidewalk is 12 ft.

Subchapter links

1 Adding and Subtracting Polynomials p.81

2 Multiplying a Polynomial by a Monomial p.81

3 Multiplying Polynomials p.81

4 Special Products p.82

5 Using the Distributive Property p.82

6 Solving x^2+bx+c=0 p.83

7 Solving ax^2+bx+c=0 p.83

8 Differences of Squares p.84

9 Perfect Squares p.84

10 Roots and Zeros p.85