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f(x)=x^4+2x^3+6x^2+18x-27
We want to write a polynomial function with integral coefficients so that f(x)=0 has the given zeros. -3, 1, -3i To do so, recall the Complex Conjugates Theorem.
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Complex Conjugates Theorem |
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If f(x) is a polynomial with real coefficients, then the complex roots of f(x)=0 occur in conjugate pairs. |
| Root | Factor |
|---|---|
| -3 | x-(-3) |
| 1 | x-1 |
| -3i | x-(-3i) |
| 3i | x-3i |
| Polynomial | f(x)= [x-(-3)] (x-1) [x-(-3i)](x-3i) |
Let's simplify the polynomial by applying the Distributive Property. For simplicity, we will start by multiplying the first two factors and the last two factors separately. [x-(-3)] * (x-1) [x-(-3i)] * (x-3i) After we find these products, we will multiply the obtained expressions.
Let's continue by finding the product of the last two factors.
- (- a)=a
(a+b)(a-b)=a^2-b^2
(a b)^m=a^m b^m
Calculate power
i^2=- 1
- a(- b)=a* b
Finding the product of these two polynomials will give us the desired polynomial function.
Distribute (x^2+9)
Commutative Property of Addition