McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
10. Roots and Zeros
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Exercise 26 Page 77

Define another variable to represent x^2.

Roots: x=0, x=- i, x=- i, x=i, x=i
Number and Type of Roots: one real root, four imaginary roots

Practice makes perfect

To solve the given equation, we will start by factoring out the greatest common factor. Then, we will use the Zero Product Property.

x^5+2x^3+x=0
x( x^4+2x^2+1 )=0
lcx=0 & (I) x^4+2x^2+1=0 & (II)

We can see in Equation (I) that x=0 is a root of the given equation. To find other roots, we will solve Equation (II). To do so, we need to define another variable. If we let z=x^2, we can rewrite Equation (II) in terms of the z-variable.

x^4+2x^2+1=0 ⇕ z^2+2z+1=0 Note that the above equation in terms of z is a quadratic equation. Let's solve it by factoring the perfect square trinomial on the left-hand side.

z^2+2z+1=0
z^2+2z+1^2=0
z^2+2* z * 1+1^2=0
(z+1)^2=0
z+1=0
z=-1

We found that the root of z^2+2z+1=0 is z=-1, which is the double root. This means that x^2=-1. Let's solve this equation! Remember that sqrt(- a)= sqrt(a)* i.

x^2 = -1
x = ± sqrt(-1)
x = ± sqrt(1)* i
x = ± 1 * i
x = ± i

Since z=-1 was a double root, x=i and x=- i are also double roots. Roots x=0, x=i, x=i, x=- i, x=- i We can see that there are five roots. One of these is real and four of these are imaginary.