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f(x)=x^4+2x^3+5x^2+8x+4
We want to write a polynomial function with integral coefficients so that f(x)=0 has the given zeros. -1, -1, 2i To do so, recall the Complex Conjugates Theorem.
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Complex Conjugates Theorem |
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If f(x) is a polynomial with real coefficients, then the complex roots of f(x)=0 occur in conjugate pairs. |
| Root | Factor |
|---|---|
| -1 | x-(-1) |
| -1 | x-(-1) |
| 2i | x-2i |
| -2i | x-(-2i) |
| Polynomial | f(x)= [x-(-1)] [x-(-1)] (x-2i)[x-(-2i)] |
Let's simplify the polynomial by applying the Distributive Property. For simplicity, we will start by multiplying the first two factors and the last two factors separately. [x-(-1)] & * [x-(-1)] (x-2i) & * [x-(-2i)] After we find these products, we will multiply the obtained expressions.
- (- a)=a
Distribute (x+1)
Distribute x
Identity Property of Multiplication
Add terms
Let's continue by finding the product of the last two factors.
- (- a)=a
(a-b)(a+b)=a^2-b^2
(a b)^m=a^m b^m
Calculate power
i^2=- 1
- a(- b)=a* b
Finding the product of these two polynomials will give us the desired polynomial function.
Distribute (x^2+4)
Distribute x^2
Distribute 2x
Identity Property of Multiplication
Add terms
Commutative Property of Addition