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Make sure you write all the terms on the left-hand side of the equation and simplify as much as possible before using the Quadratic Formula.
Roots: x=- 83, x=1
Number and Type of Roots: two real roots
We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0
⇕
x=- b± sqrt(b^2-4 a c)/2 a
We first need to identify the values of a, b, and c.
Substitute values
- (- a)=a
Calculate power
- a(- b)=a* b
a(- b)=- a * b
Multiply
Add terms
Calculate root
The roots of this equation are x= 5± 11- 6. Let's separate them into the positive and negative cases.
| x=5± 11/- 6 | |
|---|---|
| x_1=5+11/- 6 | x_2=5-11/- 6 |
| x_1=16/- 6 | x_2=- 6/- 6 |
| x_1=- 8/3 | x_2=1 |
Using the Quadratic Formula, we found that the roots of the given equation are x=- 83 and x=1. Both of them are real.