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{{ printedBook.courseTrack.name }} {{ printedBook.name }} To factor a trinomial with a leading coefficient of $1,$ we need to find two numbers whose product is the independent term.
$x_{2}−7x−8 $
In this case, we have that the constant term is $-8.$ This is a *negative* number, so for a product to be *negative*, the factors must have opposite signs (one positive and one negative).

Factor Constants | Product of Constants |
---|---|

$1$ and $-8$ | $-8$ |

$-1$ and $8$ | $-8$ |

$2$ and $-4$ | $-8$ |

$-2$ and $4$ | $-8$ |

Next, let's consider the coefficient of the linear term. $x_{2}−7x−8 $ In this case, since the linear coefficient is $-7,$ we need the sum of the factors to be $-7.$

Factors | Sum of Factors |
---|---|

$1$ and $-8$ | $-7$ |

$-1$ and $8$ | $7$ |

$2$ and $-4$ | $-2$ |

$-2$ and $4$ | $2$ |