ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Since all of the terms are on the left-hand side of the equation, we can identify the values of a, b, and c.
16x^2-8x+1=0 ⇔ 16x^2+( - 8)x+ 1=0
We see that a= 16, b= - 8, and c= 1. Let's substitute these values into the Quadratic Formula.
Since adding or subtracting zero does not change the value of a number, the numerator will simplify to 8. Therefore, we will get only one value of x.
x= 8/32 ⇔ x= 1/4
Using the Quadratic Formula, we found that the solution of the given equation is x= 14.
b We will use the Quadratic Formula to solve the given quadratic equation.
ax^2+ bx+ c=0 ⇔ x=- b± sqrt(b^2-4 a c)/2 a
Since all of the terms are on the left-hand side of the equation, we can identify the values of a, b, and c.
x^2+x+1=0 ⇔ 1x^2+ 1x+ 1=0
We see that a= 1, b= 1, and c= 1. Let's substitute these values into the Quadratic Formula.
