You have to undo each transformation, starting with the rotation of △ ABC by 90^(∘) clockwise.
A=(2,4)
B=(6,2)
C=(4,5)
Practice makes perfect
The last transformation that resulted in △ A'B'C' was a 90^(∘) rotation clockwise. To undo this transformation we have to rotate the triangle by 90^(∘) counterclockwise. However, we will start with finding the coordinates of △ A'B'C' by examining the diagram.
To rotate a point by 90^(∘) counterclockwise about the origin we draw segments from it to the origin. Next, we use a protractor to draw a second segment that is at a 90^(∘) angle counterclockwise to the first segment. To find the coordinates of the rotated vertice, we have to make the second segment the same length as the first.
If we repeat the procedure for the remaining two points, we can draw the triangle before the 90^(∘) clockwise rotation.
To reflect a point across the x-axis, we draw segments from the point towards and perpendicular to the x-axis.
By extending these segments to the other side of the x-axis and with the same length as the corresponding first segment, we have reflected the vertices across the x-axis.
Examining the diagram, we can identify the coordinates of △ ABC.
A=(2,4)
B=(6,2)
C=(4,5)
