Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 5.2
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Exercise 131 Page 308

Practice makes perfect
a We want to calculate the value of the given numeric expression using the imaginary number i. To do so, we will first recall that the imaginary unit i is the number whose square is - 1.
i^2=- 1 In our case, the square root of a negative number is not real, but it can be written using the imaginary unit. This allows us to rewrite the given expression.
sqrt(- 49)
sqrt(49)* i
7i
b We again want to calculate the value of the given expression. To do so, we can — similar as in Part A — use the fact that sqrt(a)* i = sqrt(- a).
sqrt(- 2)
sqrt(2) * i
isqrt(2)
c We want to calculate the value of the given expression using the definition of the imaginary number i.
i^2=- 1 We can evaluate the expression using this definition.
(4i)^2
â–Ľ
Evaluate
4^2 i^2
16 i^2
16(-1)
-16
d Similarly, we want to evaluate the value of the given expression containing imaginary number i. To do so, first note that when the base of a power is a product, the expression can be rewritten by putting the exponent on both factors.
(3i)^3
3^3 i^3
27 i^3
To find the power of i, keep in mind that the Commutative and Associative Properties of Multiplication hold true for imaginary numbers. This allows us to rewrite the power as a product. i^3 = i^2 * i Now — by the definition of imaginary unit — we know that i^2= - 1. i^2&= - 1 i^3&= i^2 * i= - 1 * i= - i Therefore, indeed i^3=- i. Finally, let's use this fact to simplify the given expression.
27i^3
27( - i)
- 27i