Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 5.2
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Exercise 112 Page 301

We are given an equation and asked to solve it with the Quadratic Formula, which we can do when the equation is written in the form ax^2+bx+c=0. To solve the equation by completing the square, write it in the form x^2+bx=c.

No solution. In both cases we need to take a square root of a negative number, which we cannot do.

Practice makes perfect
To solve the given equation with the Quadratic Formula, we have to write it in the form ax^2+bx+c=0.
x^2+6x+11=0
x=-6±sqrt(6^2-4(1)(11))/2(1)
x=-6±sqrt(36-44)/2
x=-6±sqrt(-8)/2
We cannot take a square root of a negative number, so our equation has no solution. Let's check this result by completing the square. To do so, we have to write it in the form x^2+bx=c. Then, to complete the square we add the square of half the coefficient of x to both sides of the equation.
x^2+6x+11=0
x^2+6x=- 11
x^2+6x+(6/2)^2=- 11+(- 6/2)^2
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Simplify
x^2+6x+(3)^2=- 11+(3)^2
x^2+6x+9=-11+9
x^2+6x+9=-2
x^2-2(x)(3)+3^2=-2
(x+3)^2=-2
x+3 = ± sqrt(-2)
Again, to proceed further we would have to take a square root of a negative number. Both methods gave the same answer — our equation has no solution.