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We have been given the opposite leg and the hypotenuse.
We have been given the adjacent leg and the hypotenuse.
We have been given the opposite and adjacent leg.
Equation: sin θ = 6/9
Solution: θ ≈ 0.73
Equation: cos α = 5/7
Solution: θ ≈ 0.78
Equation: tan β = 7/9
Solution: θ ≈ 0.66
Here we want to relate the opposite leg and the hypotenuse to the reference angle θ. To do that we should use the sine ratio.
sin θ = Opposite/Hypotenuse
By substituting the given sides and angle, we get a trigonometric equation relating the side lengths and θ.
We have the following equation for θ. sin θ = 6/9 Let's solve using the inverse sine function.
a/b=.a /3./.b /3.
sin^(-1)(LHS) = sin^(-1)(RHS)
Use a calculator
Round to 2 decimal place(s)
Here we want to relate the adjacent leg and hypotenuse to the reference angle θ. To do that we should use the cosine ratio.
cos α = Adjacent/Hypotenuse
Let's solve it using the inverse cosine function.
Here, we want to relate the opposite and adjacent leg to the reference angle θ. To do that we should use the tangent ratio.