Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 10.2
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Exercise 70 Page 572

Practice makes perfect
a Before we can find the inverse of the given function, we need to replace f(x) with y.
f(x)=7x-2 ⇔ y=7x-2Now, to algebraically determine the inverse of the given equation we exchange x and y and solve for y. Given Equation & Inverse Equation y=7 x-2 & x=7 y-2 The result of isolating y in the new equation will be the inverse of the given function.
x=7y-2
â–Ľ
Solve for y
x+2=7y
7y=x+2
y=x+2/7
Finally, we write the inverse of the given function in function notation by replacing y with f^(- 1)(x) in our new equation. f^(- 1)(x)=x+2/7
b We want to show that the inverse function found in Part A is correct. To do this, we will choose an input number for the function f(x) and evaluate. Let's choose x= 1 and calculate f( 1).
f(x)=7x-2
f( 1)=7( 1)-2
â–Ľ
Evaluate
f(1)=7-2
f(1)=5

With an input number of 1 we obtained the output number of 5.

Let's now evaluate the inverse function with the obtained output number as an argument.
f^(- 1)(x)=x+2/7
f^(- 1)( 5)=5+2/7
â–Ľ
Evaluate
f^(- 1)(5)=7/7
f^(- 1)(5)=1
As we can see, our final output is the same as original input.

Therefore, the inverse function found in Part A is correct.