2. Section 10.2
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Graphing Form:& y=a(x- h)^2+ k Vertex:& ( h, k) To identify the vertex we have to rewrite the right-hand side to match the graphing form. Graphing Form:& y=- (x-( - 4))^2+ 1 Vertex:& ( - 4, 1) As we can see, the parabola has its vertex at (- 4,1). Additionally, notice that the coefficient to (x+4)^2 is negative, which means the parabola opens downwards.