Core Connections Integrated II, 2015
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Core Connections Integrated II, 2015 View details
2. Section 10.2
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Exercise 97 Page 583

Practice makes perfect
a The sum of the central angles of a circle equals 360^(∘). Therefore, by dividing 360^(∘) by 9 we can calculate the central angle.

360^(∘)/9=40^(∘)

b The arc mAD refers to the arc that does not pass through B and C. Let's highlight this arc in red and add the measure of ∠ B to the diagram.

Examining the diagram, we notice that ∠ B and ∠ C are both inscribed angles to the same intercepted arc. This must means that they have the same measure. m∠ C= m∠ B ⇔ m∠ C = 97^(∘) Also, the intercepted arc is always twice the measure of a corresponding inscribed angle. This must mean that mAD can be obtained by multiplying the measure of m∠ B by 2. mAD =2(97^(∘))=194^(∘)

c Let's add the given information to the diagram. Also, AB refers to the minor arc highlighted below.

The intercepted arc has the same measure as its corresponding central angle. Therefore, if m∠ ACB=125^(∘) then mAB=125^(∘). To find the arc length AB, we have to multiply the circumference of the circle with the ratio of the central angle to 360^(∘). AB=2π(8)* 125^(∘)/360^(∘)≈ 17.5 units The arc length is about 17.5 units. To find the area of the sector, we multiply the area of the circle with the ratio of the central angle to 360^(∘). A=π(8)^2* 125^(∘)/360^(∘)≈ 69.8 squared units The area of the sector is about 69.8 squared units.