Sign In
| 10 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Magdalena has just found an old printer toy she used to play with when she was a child. She discovered that the toy prints random functions as labels.
Review the definitions of linear, quadratic, and exponential functions.
Linear Function | y=2x+1 |
---|---|
Quadratic Function | y=x2+3x+1 |
Exponential Function | y=3⋅2x |
In the following applet, determine whether the given function is linear, quadratic, or exponential.
When considering a table of values, the trend of the data can be determined by observing how the dependent variable changes over equal intervals. To do so, the following situations need to be analyzed.
The applet below illustrates each situation.
Magdalena's father works as a manager for a fish farming company. This morning, Magdalena and her brother Vincenzo poked around in her father's briefcase. They found some papers containing information about the fish population in three nearby lakes.
Fish Population (Thousands) | |||
---|---|---|---|
Time (Months) | Lake Verdastro | Lake Rumoroso | Lake Mezzo |
0 | 1356 | 721 | 1207 |
1 | 6676 | 2163 | 3007 |
2 | 11996 | 6489 | 7807 |
3 | 17316 | 19467 | 15607 |
4 | 22636 | 58401 | 26407 |
Lake Verdastro: Linear Function
Lake Rumoroso: Exponential Function
Lake Mezzo: Quadratic Function
The y-values have a common difference in a linear function, while in an exponential function, the y-values have a common ratio. Furthermore, in a quadratic function, the second differences are constant.
Lake | Model |
---|---|
Verdastro | Linear Function |
Rumoroso | Exponential Function |
Mezzo | Quadratic Function |
Note that the analysis suggests that Lake Rumoroso is the best for fish farming. The children gave this information to their father, who was delighted by this excellent analysis and took them for ice cream as a reward.
Magdalena will start college soon, so she decided to start saving money to buy a new computer. The computer she wants costs around $2000. Thanks to her help with the analysis for the fish farming company, her father gave Magdalena an initial amount of $1000. She plans to add $40 to her savings each week.
Magdalena wants to buy the computer as soon as possible. She thinks she will be able to afford it after 30 weeks of saving the money but she isn't sure. Answer the following questions to help her discover if she will save enough money for the new computer by then.
x=30
Multiply
Add terms
Magdalena is happy with her new computer. She is also using it for her part-time job as a designer to help pay for her school expenses. She sells 50 designs per month at $59 each. However, because creating each design is complex, she plans to increase the price of each design. She estimates that for each $5 increase, two fewer designs will be sold per month.
Magdalena wants to know what price will maximize her revenue, or the amount of money she makes. Identify the following information to help Magdalena make the best decision about her small business.
S(x)=50−2x, N(x)=59+5x
Distribute 50−2x
Commutative Property of Multiplication
Distribute 59&5x
Add terms
Commutative Property of Addition
Vincenzo, Magdalena's little brother, loves dinosaurs. He wants to make a 10-minute film for a school assignment, explaining the history of this extinguished group of reptiles. He asked Magdalena to help him make and edit the video on her computer. However, the siblings are worried because Vincenzo has a USB drive with only 16GB to store the film on.
After some research, Magdalena found that any high-quality video file requires an initial storage space of 20MB. This required storage space doubles for each additional minute. The children now have to investigate whether the USB drive has enough space for Vincenzo's completed film. Find the following information to help them.
Function: f(x)=20⋅2x
x=10
Calculate power
Multiply
See solution.
Begin by analyzing the behavior of the functions. Do all functions have a turning point? What is the maximum number of x-intercepts each function could have?
Three distinctive characteristics of quadratic functions will be identified one at a time.
Linear and exponential functions either only increase or only decrease. Conversely, quadratic functions always decrease and increase. The order depends on the direction in which the parabola opens.
Because a parabola either opens upward or downward, there is always one point that is the absolute minimum or absolute maximum of the function. This point is called the vertex.
Using this information, a third distinctive characteristic of quadratic functions can be determined.
While non-horizontal linear functions and exponential functions have at most one x-intercept, quadratic functions can have up to two x-intercepts.
Only three distinctive characteristics of quadratic functions are presented here. Please note that there are a few others.
Three Distinctive Characteristics of Quadratic Functions |
---|
Linear and exponential functions either only increase or only decrease. Conversely, quadratic functions always decrease and increase. The order depends on the direction in which the parabola opens. |
Because a parabola either opens upward or downward, there is always one point that is the absolute minimum or absolute maximum of the function. This point is called the vertex. |
While non-horizontal linear functions and exponential functions have at most one x-intercept, quadratic functions can have up to two x-intercepts. |
Consider the following graphs.
By examining the functions, we can see that we have a linear function, two exponential functions, and one quadratic function. We know that this is the case because the linear function has the form y=mx+b, the degree of the x-variable in the quadratic function is 2, and in exponential functions, the variable x appears in an exponent. lcl y = 2x+1 & → & linear [0.4em] y = 2^x+2 & → & exponential [0.4em] y = 0.5^x+2 & → & exponential [0.4em] y = 2x^2+2 & → & quadratic Let's now start matching the functions with the graphs.
A linear function is graphically represented by a straight line. We can only see one graph that is a straight line and that is graph B. Therefore, we should match the linear function with B. B → y=2x+1
The graph of a quadratic equation has the form of a parabola, a curve that is symmetric along the vertical line that passes through its vertex. There is only one graph that exhibits these characteristics, graph D. D → y=2x^2+2
Of the two remaining graphs, both exponential functions, we can see that one represents an increasing function and the other represents a decreasing function.
An increasing exponential function has a base, or constant multiplier, greater than 1. Conversely, a decreasing exponential function has a base that is less than 1 but greater than 0. Increasing:& y = ab^x b>1 Decreasing:& y = ab^x 0
The graphs of two functions are shown on the first quadrant of a coordinate plane.
We will analyze f(x) and g(x) one at a time.
Let's identify three points on the graph of f(x).
Since we know that the graph is not a line, the first differences are not constant. Let's calculate the second differences.
The second differences are not constant. Therefore, f(x) is not a quadratic function. Let's see if it is an exponential function by checking whether the y-coordinates of these points have a common ratio.
The y-values of consecutive data points have a common ratio. This means that f(x) is an exponential function.
Let's start by identifying some points on the graph of g(x).
We already know that g(x) is not a linear function. Just as we did for f(x), we will analyze the second differences between consecutive data points.
Here, the second differences are constant. Therefore, we do not need to analyze if there is a common ratio because we already know that g(x) is a quadratic function. The correct choice is A.
Diego wants to write a function that satisfies the following conditions.
The function that Diego wants to write has constant second differences but not constant first differences. Therefore, we know that this is a quadratic function.
Let's recall the standard form of a quadratic function. y = ax^2+bx+c We know that the y-intercept is 4. This means that the value of c is 4. y = ax^2+bx+4 Next, because we know that the parabola passes through ( 1, 6) and ( - 1, 4), we can form a system of equations with a and b as its variables. 6 = a( 1)^2+b( 1)+4 & (I) 4 = a( - 1)^2+b( - 1)+4 & (II) Let's solve the system by using the Elimination Method. To do so, we will first simplify the equations.
Now, we can add Equation (I) to Equation (II).
Finally, we will substitute 1 for a in Equation (I).
Now that we know that both a and b are equal to 1, we can write the quadratic function. y=1x^2+1x+4 ⇕ y=x^2+x+4