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x_2= 2, x_1= - 2
a-(- b)=a+b
Add terms
|4|=4
We now want to know the coordinates for corners of the quadrilateral. Since each side of the square is 4 units, the midpoints are 2 units away. Let's draw the quadrilateral without the square around it.
Substitute ( 0,2) & ( 2,0)
Segment | AB | BC | CD | DA |
---|---|---|---|---|
Length | 2sqrt(2) | 2sqrt(2) | 2sqrt(2) | 2sqrt(2) |
Substitute ( 2,0) & ( 0,2)
Subtract terms
Calculate quotient
Segment | AB | BC | CD | DA |
---|---|---|---|---|
Slope | -1 | 1 | -1 | 1 |
When we multiply the two slopes, m_(AB) and m_(DA), with each other we get m_(AB)* m_(DA)=1* (- 1)=- 1. Since the product is - 1 we know that the lines are perpendicular and that the angle is right. Now we check the others:
Segments | AB & BC | BC & CD | CD & DA | DA & AB |
---|---|---|---|---|
Product of Slopes | -1 | -1 | -1 | -1 |
Since all four products are -1, we have four right angles. A quadrilateral with four sides of equal length and with four right angles is called a square.
Substitute ( 2,0) & ( 0,2)
Subtract terms
Calculate power
Add terms
The length of the square's sides is s_s=sqrt(8) units. We calculate the area of a square using the formula A=s^2. Here the area is A=s_s^2=( sqrt(8) )^2=8 square units. We find the perimeter by adding the sides of the square. With four sides each having the length sqrt(8) units the perimeter is P=4* s_s=4* sqrt(8)≈ 11.31 units. The square we started out with had the area 16 square units. This smaller square's area is 8 which is half the area of the bigger square.