Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
6. Arithemetic Sequences
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Exercise 44 Page 205

Practice makes perfect
a We have been given three figures we can describe as circles divided into sectors. Let's see if they follow a pattern.
Figure Number of Sectors
1 2
2 4
3 6
For each figure the number of sectors is two more than for the previous figure. By continuing this pattern we can determine how many sectors the next three figures must be divided in.
Figure Number of Sectors
1 2
2 4
3 6
4 8
5 10
6 12

We are now going to draw these, one at the time. Let's begin with the circle with eight sectors.

Circle divided into 8 sectors.

Our next diagram will show a circle divided into ten sectors.

Circle divided into 10 sectors.

Our final image will be of a circle which has been divided into a total of twelve sectors.

Circle divided into 12 sectors.
b To describe the 20th figure we can write an equation for our sequence. Let's recall the equation for an arithmetic sequences for which the first term is a_1 and the common difference is d.
a_n= a_1+(n-1) dWe know that with each new figure 2 sectors are being added. Therefore, our common difference is 2. We also know that since the first figure is divided into 2 sectors the first first term of the sequence is 2. a_n= a_1+(n-1) d ⇓ a_n= 2+(n-1) 2 By substituting 20 for n in the equation, we can find out how many sectors the 20th figure has.
a_n=2+(n-1)2
a_(20)=2+( 20-1)2
â–Ľ
Simplify right-hand side
a_(20)=2+40-2
a_(20)=40
The 20th figure will have 40 sectors.