Exercise 16 Page 204

Using equivalent fractions, rewrite the terms so that all the fractions have denominator 6.

1/6, 0, -1/6

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By observing the change that occurs between consecutive terms, we can describe the pattern of the arithmetic sequence. Before we do that, let's expand the fractions to have a common denominator of 6.

Sequence	5/6, 2/3, 1/2, 1/3
Expand	5/6, 2* 2/3* 2, 1* 3/2* 3, 1* 2/3* 2
Simplify	5/6, 4/6, 3/6, 2/6

Here, we see that to get from a term to the next term we subtract 16. Therefore, the common difference of the sequence is - 16. 5/6+( - 16) ⟶4/6+( - 16) ⟶3/6+( - 16) ⟶2/6 To find the next three in the sequence, we will extend this pattern three times. 5/6& +( - 16) ⟶4/6+( - 16) ⟶3/6+( - 16) ⟶2/6 ... & +( - 16) ⟶ 1/6 +( - 16) ⟶ 0 +( - 16) ⟶ - 1/6 Therefore, the next three terms are 16, 0, and - 16.

Subchapter links

Communicate Your Answer p.199

Monitoring Progress p.200-203

Exercises p.204-206

Exercise 16 Page 204

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