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| 14 Theory slides |
| 9 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Consider the graph of the parent absolute value function.
Transformations of y=∣x∣ | |
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Vertical Translations | Translation up k units, k>0y=∣x∣+k
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Translation down k units, k<0y=∣x∣+k
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Horizontal Translations | Translation to the right h units, h>0y=∣x−h∣
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Translation to the left h units, h<0y=∣x−h∣
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Tadeo just learned about translations of absolute value functions. He believes in the motto that practice makes perfect, so he decides to study more. The following graphs are the graphs of the absolute value parent function after a certain translation.
Compare the given graphs to the graph of the absolute value parent function to identify the translation applied to each graph.
Begin by identifying the translation of each graph when compared to the graph of the absolute value parent function f(x)=∣x∣.
Now that the translations have been identified, recall the translation rules.
Transformations of y=f(x) | |
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Horizontal Translations | Translation to the right by h units, h>0y=f(x−h)
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Translation to the left by h units, h<0y=f(x−h)
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Vertical Translations | Translation upwards byk units, k>0y=f(x)+k
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Translation downwards by k units, k<0y=f(x)+k
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The graph of an absolute value function y=∣x∣ can be translated vertically by adding a number to — or subtracting from — the function rule. Likewise, it can be also translated horizontally by adding a number to — or subtracting from — the rule's input.
The following applet shows the graph of an absolute value function in the form of f(x)=∣x−h∣+k, where h and k are integers. Considering the translation rules, determine the values of h and k.
Transformations of f(x) | |
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Vertical Stretch or Shrink | Vertical stretch, a>1 y=af(x) |
Vertical shrink, 0<a<1 y=af(x) |
Transformations of f(x) | |
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Horizontal Stretch or Shrink | Horizontal stretch, 0<b<1 y=f(bx) |
Horizontal shrink, b>1 y=f(bx) |
Transformations of y=∣x∣ | |
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Vertical Stretch or Shrink | Vertical stretch, a>1y=a∣x∣
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Vertical shrink, 0<a<1y=a∣x∣
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Horizontal Stretch or Shrink | Horizontal stretch, 0<b<1y=∣bx∣
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Horizontal shrink, b>1y=∣bx∣
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Emily uses a water tank that contains 10 cubic meters of water to water her plants. She drains the water tank from one faucet and then refills it from another identical faucet.
The following graph models the water level of the tank when it is drained and then refilled after t minutes.
Transformations of f(x) | |
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Reflections | In the x-axis y=-f(x) |
In the y-axis y=f(-x) |
Transformations of y=∣x∣ | |
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Reflections | In the x-axisy=-∣x∣
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In the y-axisy=∣-x∣
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W.Write the equation of the reflected function by determining the type of the reflection.
W,begin by graphing the given function by using a table of values.
x | f(x)=∣2x−5∣ | f(x) |
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-1 | f(x)=∣2(-1)−5∣ | 7 |
0 | f(x)=∣2(0)−5∣ | 5 |
1 | f(x)=∣2(1)−5∣ | 3 |
2.5 | f(x)=∣2(2.5)−5∣ | 0 |
4 | f(x)=∣2(4)−5∣ | 3 |
5 | f(x)=∣2(5)−5∣ | 5 |
6 | f(x)=∣2(6)−5∣ | 7 |
Now plot the ordered pairs and connect them to graph the absolute value function.
x | f(x)=21∣x−4∣−2 | f(x) |
---|---|---|
-2 | f(x)=21∣-2−4∣−2 | 1 |
0 | f(x)=21∣0−4∣−2 | 0 |
2 | f(x)=21∣2−4∣−2 | -1 |
4 | f(x)=21∣4−4∣−2 | -2 |
6 | f(x)=21∣6−4∣−2 | -1 |
8 | f(x)=21∣8−4∣−2 | 0 |
10 | f(x)=21∣10−4∣−2 | 1 |
Plot the ordered pairs and draw the graph.
An absolute value function can be translated 4 units to the left by adding 4 to the input of the function.
Original Function | Translated Function |
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f(x) = 3|x+1|-6 | g(x)=f(x +4) ⇓ g(x)=3|(x+ 4)+1|6 ⇓ g(x)=3|x+5|-6 |
Next, to vertically shrink the resulting function by a factor of 23, we will multiply the output of the function by 23.
Original Function | Translated Function | Shrunk Function |
---|---|---|
f(x) = 3|x+1|-6 | g(x)=f(x +4) ⇓ g(x)=3|(x+ 4)+1|-6 ⇓ g(x)=3|x+5|-6 |
h(x)= 2/3g(x) ⇓ h(x)= 2/3(3|x+5|-6) ⇓ h(x)=2|x+5|-4 |
Comparing h(x) to the functions that Mark and Zosia found, we can see that Zosia has subtracted 4 from the input instead of adding. Also, it seems that Mark did not multiply the whole output by 23 — he forgot to distribute the 23 to the -6 constant. Therefore, neither of them is correct.
Let's look at all of the possible transformations we can perform to a function so that we can more clearly identify what is happening to our absolute value function.
Transformations of f(x) | |
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Vertical Translations | Translation up k units, k>0 y=f(x)+ k |
Translation down k units, k>0 y=f(x)- k | |
Horizontal Translations | Translation right h units, h>0 y=f(x- h) |
Translation left h units, h>0 y=f(x+ h) | |
Vertical Stretch or Compression | Vertical stretch, a>1 y= af(x) |
Vertical compression, 0< a< 1 y= af(x) | |
Horizontal Stretch or Compression | Horizontal stretch, 0< b<1 y=f( bx) |
Horizontal compression, b>1 y=f( bx) | |
Reflections | In the x-axis y=- f(x) |
In the y-axis y=f(- x) |
Now let's look at the given function. g(x)=f(x +3) Looking at the table, we can see that this is a horizontal translation of f to the left 3 units. To determine the points of g, we can decrease the x-coordinates of the points of f by 3. The y-coordinates will remain the same because no vertical shift takes place. The following table gives the transformed points.
Points on f(x) | f(x+3) | Points on g(x) |
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A(- 1,7) | (- 1- 3,7) | A'(- 4,7) |
B(1/2,4) | (1/2- 3,4) | B'(-5/2,4) |
C(2, 5) | (2- 3, 5) | C'(- 1, 5) |
Normally we would take the parent function f(x)=|x| and transform it into a more complex function such as the one we are given.
g(x)=3|4x-2|-1
We would look at each of the transformations individually and work our way from the inside
to the outside.
Parent Function | y=|x| |
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Horizontal Translation to the Right 2 Units | y=|x- 2| |
Horizontal Shrink by a Factor of 4 | y=| 4x-2| |
Vertical Stretch by a Factor of 3 | y= 3|4x-2| |
Vertical Translation Down 1 Unit | y=3|4x-2| -1 |
In this case, we have been asked to transform a complex function g(x) back into the parent function f(x). This means that we have to reverse the process. Let's do it!
Given Function | y=3|4x-2|-1 |
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Vertical Translation Up 1 Unit | y=3|4x-2|-1 +1 ⇕ y=3|4x-2| |
Vertical Shrink by a Factor of 13 | y= 1/3(3|4x-2|) ⇕ y=|4x-2| |
Horizontal Stretch by a Factor of 14 | y=|4( 1/4x)-2| ⇕ y=|x-2| |
Horizontal Translation to the Left 2 Unit | y=|(x +2)-2| ⇕ y=|x| |
We have successfully arrived back at the parent function. To see the changes, we can draw both absolute value functions on the same coordinate plane.