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The area of a rectangle is calculated by multiplying the base with the height.

The area is then $6x_{2}.$ b

We will determine $x$ by substituting $54$ for $A$ and solve the resulting equation.

$A=6x_{2}$

Substitute$A=54$

$54=6x_{2}$

RearrangeEqnRearrange equation

$6x_{2}=54$

DivEqn$LHS/6=RHS/6$

$x_{2}=9$

SqrtEqn$LHS =RHS $

$x=±9 $

CalcRootCalculate root

$x=±3$

$x>0$

$x=3$

We can exclude the negative root, since lengths must be positive. This means that $x=3$ and that $2x=2⋅3=6and3x=3⋅3=9.$ The rectangle's side lengths are $6$ and $9$ units