Solving Quadratic Equations with Square Roots

We will solve the equation and then compare our solution with Ron-Jon's work. To solve the equation using square roots, we have to start by isolating

x

on the left-hand side of the equation.

2 x^{2} - 33 = 39

AddEqn

LHS + 33 = RHS + 33

2 x^{2} = 72

DivEqn

LHS / 2 = RHS / 2

x^{2} = 36

So far our solution is identical with the given work. Our next step will be taking the square root of each side. Don't forget that when solving an equation this way we must consider both the positive and the negative square roots.

x^{2} = 36

SqrtEqn

LHS = RHS

x = \pm 36

CalcRootCalculate root

x = \pm 6

Therefore, the solutions to the equation are

x = 6

and

x = - 6 .

Ron-Jon forgot the negative square root of

36 .

Solving Quadratic Equations with Square Roots 1.17 - Solution