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First we want to isolate the $x_{2}$-term. After that we can square root both sides of the equation.

The equation then has two real solutions: $x=9$ and $x=-9.$

b

Our $x_{2}$-term stands alone on the left side, so in order to solve the equation we take the square root of both sides. But we cannot calculate the square root of $-121.$ That is because there is no real number whose square is negative. Therefore, the equation has **no real solutions**.

c

After we have isolated the $x_{2}$-term we can write the equation as
$x_{2}=-1.$
Just like in Part B, this is an equation that **lacks real solutions**, because we must take the square root of a negative number to solve it.

d

Let's isolate the $x_{2}$-term on one side. After that we can square root both sides.

$x_{2}−145=-45$

AddEqn$LHS+145=RHS+145$

$x_{2}=100$

SqrtEqn$LHS =RHS $

$x=±100 $

CalcRootCalculate root

$x=±10$