Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
8. Perimeter, Circumference, and Area
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Exercise 61 Page 67

Start with finding the side length of the garden. Model the garden and the walkway.

1104 ft^2

Practice makes perfect
We have been given a square garden with a perimeter of 260 ft and a 4-ft walkway around it. In order to find the area of the walkway, let's find the side length of the garden and draw a model for it. In order to find the perimeter of a square with a side length a, we use the following formula. P=4 s Let's substitute 260 for P to find the side length.
P=4s
260=4s
260/4=4s/4
65=s
s=65
Thus, the side length of the garden is 65 ft. Now, we can model the garden and the walkway around is as the following.

Adding the width of the walkway to the length and width of the garden, we see that the walkway is 73 ft by 73 ft. Base:& 4+ 65+ 4=73 Height:& 4+ 65+ 4=73 Next, we will separate the walkway into small rectangles to find its area.

Since we have four identical rectangles, it is enough to find the area of only one of them. The area formula for a rectangle with a base b and a height h is the following. A= b h The rectangles have a base 69 ft and height of 4 ft. Let's substitute values into the formula.
A=bh
A= 69* 4
A=276
As a result, the area of the one of the rectangles is 276 ft^2. Since there are four identical rectangles, we can find the area of the walkway A_W as the following.
A_W=4A
A_W=4* 276
A_W=1104
Thus, the area of the walkway is 1104 ft^2.