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Pearson Algebra 1 Common Core, 2011 View details

Chapter Review

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Exercise 27 Page 154

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

No solution.

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the right-hand side of the equation.

5n=20(4+0.25n)

Distr

Distribute 20

5n=4*20+0.25n*20

Multiply

5n=80+5n

SubEqn

LHS-5n=RHS-5n

5n-5n=80+5n-5n

SubTerm

Subtract term

0 ≠ 80