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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 25 Page 154

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

7.2

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other using the Properties of Equality. In this case, we start by subtracting 6 from both sides of the equation.

6-0.25f=f-3
SubEqn

LHS-6=RHS-6

6-0.25f-6=f-3-6
SubTerm

Subtract term

-0.25f=f-9
SubEqn

LHS-f=RHS-f

-0.25f-f=f-9-f
SubTerm

Subtract term

-1.25f=-9
DivEqn

.LHS /(-1.25).=.RHS /(-1.25).

-1.25f/-1.25=-9/-1.25
DivNegNeg

- a/- b=a/b

1.25f/1.25=9/1.25
UseCalc

Use a calculator

f=7.2

The solution to the equation is f=7.2.

Subchapter links expand_more
arrow_right Exercises p.152-156
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Exercises 7 (Page 153)
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Exercises 24 (Page 154)
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