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Pearson Algebra 1 Common Core, 2011 View details

Chapter Review

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Exercise 9 Page 153

Start by using the Multiplication Property of Equality.

65

Practice makes perfect

To solve the equation, we have to isolate x on one side. We will begin by multiplying both sides by 5. This is allowed by the Multiplication Property of Equality.

n/5=13

MultEqn

LHS * 5=RHS* 5

n/5* 5=13* 5

FracMultDenomToNumber

a/5* 5 = a

n=13* 5

Multiply

n=65

Therefore, n=65 is the solution to the equation. To check that we have the correct solution, we can substitute n=65 into the original equation and simplify.

n/5=13

Substitute

n= 65

65/5? =13

CalcQuot

Calculate quotient

13=13

Since the left-hand side and the right-hand side are equal, n=65 is the correct solution.