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Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 49 Page 155

You can solve for the variable by using cross products.

-1

Practice makes perfect

To solve the proportion, we will start by using cross products. Remember that we will need to treat 2c-3 and 7c+4 as single quantities in the cross multiplication process.

5/2c-3=3/7c+4
CrossMult

Cross multiply

5(7c+4)=3(2c-3)
Distr

Distribute 5 & 3

35c+20=6c-9
SubEqn

LHS-6c=RHS-6c

35c+20-6c=6c-9-6c
SubTerm

Subtract term

29c+20=-9
SubEqn

LHS-20=RHS-20

29c+20-20=-9-20
SubTerm

Subtract term

29c=-29
DivEqn

.LHS /29.=.RHS /29.

29c/29=-29/29
CalcQuot

Calculate quotient

c=-1

When c=-1, the ratios are proportional.

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