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Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
Chapter Review
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Exercise 48 Page 155

You can solve for the variable by using cross products.

39

Practice makes perfect
To solve the proportion, we will start by using cross products. Remember that we will need to treat b+3 and b-3 as single quantities in the cross multiplication process.
b+3/7=b-3/6
CrossMult

Cross multiply

6(b+3)=7(b-3)
Distr

Distribute 6

6b+18=7(b-3)
Distr

Distribute 7

6b+18=7b-21
SubEqn

LHS-7b=RHS-7b

- b+18=- 21
SubEqn

LHS-18=RHS-18

- b=- 39
MultEqn

LHS * (-1)=RHS* (-1)

b=39
When b=39, the ratios are proportional.
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arrow_right Exercises p.152-156
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Exercises 7 (Page 153)
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