Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
5. Solving Rational Equations
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Exercise 45 Page 696

Find what fraction of time was each step of the work. Then, write a ratio for the work done in each step considering what fraction of time was spent doing so.

11 13 hours

Practice makes perfect
Let's begin by making sense of the given information. We are told that one day Sumi and her apprentice work together for 2 hours and 16 minutes. Then, Sumi keeps working alone for an additional 4 hours and 32 minutes. Let's use a conversion factor to write the minutes as hours.
16 min * 1 h/60 min
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Simplify
16min * 1h/60min
16 min * 1h/60 min
16h/60
4h/15
4/15h
They worked together for 2 415 hours. Let's now write this mixed number as a fraction.
2 415
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Write mixed number as a fraction
2* 15 + 4/15
30+4/15
34/15
Let's do the same for the time Sumi worked alone!
Time a bc Time (h)
Working Together 2 h 16 min 2 415 34/15
Sumi Alone 4 h 32 min 4 815 68/15
Next, we will find the total time spent on this work. 34/15+ 68/15= 102/15 We can find what fraction of time was each step of the work by dividing by this time. Let's find what fraction of time they worked together!
Fraction of Time=Time/Total Time
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Simplify right-hand side
Fraction of Time=3415/10215
Fraction of Time=34/15*15/102
Fraction of Time=34* 15/15* 102
Fraction of Time=34* 15/15* 3* 34
Fraction of Time=34*15/15* 3 * 34
Fraction of Time=1/3
In a similar way, we can find what fraction of time Sumi worked alone.
Time Time/Total Time Fraction of Time
Working Together 34/15 3415/10215 1/3
Sumi Alone 68/15 6815/10515 2/3

We are told that Sumi can wash the windows from a building in 34 the time it takes her apprentice. Let t be the time it takes her apprentice to wash all the windows. We can write an expression for the time it takes each person if working individually. Sumi:& 3/4t Apprentice:& t We can now write a ratio for the fraction of the work done in each part of the work.

Ratio Fraction of Time Fraction of Work
Working Together 1/t+1/34t 1/3 1/3( 1/t+1/34t)
Sumi Alone 1/34t 2/3 2/3( 1/34t)
Since the whole work was done in 10215 hours, we can write an equation for t by adding each fraction of the work done. 1/3 ( 1/t+1/34t ) + 2/3 ( 1/34t ) =1/10215 Let's solve this equation!
1/3 ( 1/t+1/34t ) + 2/3 ( 1/34t ) =1/10215
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Solve for t
1/3(1/t+4/3t)+2/3(4/3t)=15/102
1/3(1/t)+1/3(4/3t)+2/3(4/3t)=15/102
1/3t+4/9t+8/9t=15/102
3/9t+4/9t+8/9t=15/102
15/9t=15/102
15=15/102* 9t
15* 102=15* 9t
102=9t
102/9=t
34/3=t
t=34/3
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Write fraction as a mixed number
t=33+1/3
t=33/3+1/3
t=11+1/3
t=11 13
Therefore, the apprentice would take 11 13 hours if working alone.