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Can you rewrite the right-hand side of the equation so that it is a rational expression?
See solution.
We are asked how we could use the Cross Products Property to solve the given equation.
1/x-2=2x-6/x+6+1
The Cross Products Property can be used when both sides of the equation are rational expressions. Recall that a rational expression is a fraction whose numerator and denominator are polynomials. In our case, the left-hand side of the equation is a rational expression but the right-hand side is not.
| Expression | Is It a Rational Expression? |
|---|---|
| 1/x-2 | Yes ✓ |
| 2x-6/x+6+1 | No * |
Before we can use the Cross Products Property, we have to rewrite the right-hand side of our equation as a rational expression. We can do it by rewriting 1 as a rational expression with a denominator of x+6. In doing so, we will obtain a sum of two rational expressions with a common denominator. Then we can add the expressions.
Rewrite 1 as x+6/x+6
Add fractions
Add terms
We rewrote the right-hand side of the equation as a rational expression. 1/x-2=2x-6/x+6+1 ⇔ 1/x-2=3x/x+6 The newly obtained form of our original equation allows us to use the Cross Products Property to solve it.
Cross multiply
Identity Property of Multiplication
Distribute 3x
We obtained a quadratic equation. To solve it, we need to use the Quadratic Formula. x=- b±sqrt(b^2-4 a c)/2 a The values a, b, and c correspond with the values of a quadratic equation written in standard form, ax^2+ bx+ c=0. In our case, a= 3, b= - 7, and c= - 6. We can substitute these values into the above formula and simplify.
Substitute values
We got that the solutions for this equation are x= 7±116. Next, we should separate them into the positive and negative cases.
| x=7±11/6 | |
|---|---|
| x_1=7+11/6 | x_2=7-11/6 |
| x_1=18/6 | x_2=- 4/6 |
| x_1=3 | x_2=-2/3 |
Using the Quadratic Formula, we found that the solutions of the given equation are x_1=3 and x_2=- 23. Note that since the original equation contained rational expressions, we have to check for extraneous solutions.
| x_1=3 | x_2=- 23 | |
|---|---|---|
| Substitute | 1/3-2? =2( 3)-6/3+6+1 | 1/- 23-2? =2( - 23)-6/- 23+6+1 |
| Simplify | 1=1 | -3/8=-3/8 |
| Is Valid? | Yes ✓ | Yes ✓ |
Neither x_1=3 nor x_2=- 23 are extraneous, so these are the solutions of the given equation.